Re: Administrivia: List Announcement
Benjamin A. Okopnik disse:
> l1 = strlen(p1);
I think that there we need to code:
> l1 = strlen(buf1);
> s1 = sizeof(buf1);
> l2 = strlen(buf2);
> s2 = sizeof(buf2);
but, I coded and the results:
# ./a.out `perl -e 'print "A" x 251;print " "; print "B" x 251'`
strlen1: 251 sizeof1: 4
strlen2: 251 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 251'`
strlen1: 254 sizeof1: 4
strlen2: 251 sizeof2: 4
# ./a.out `perl -e 'print "A" x 253;print " "; print "B" x 251'`
Segmentation fault
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 252'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 251;print " "; print "B" x 252'`
strlen1: 251 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 253'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 254'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 255'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
mmm... it seems that buf2 overflowed 2 bytes. try other sizes for SIZE.
I have tried 248 and 250. it's amazing that doesn't sigfaults.
seems a very special condition.
Edinelson Keiji Shimokawa.
A jedi prentice owned by Dark Force.
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Received on Wed May 14 12:28:33 2003
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: Wed Aug 23 2006 - 14:07:39 EDT
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